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  • Yellow line indicator

    I can't find any information what the yellow line indicator means... Somebody knows?
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    It seems like the memory is full, but compiler says:
    No Errors, code size = 9112 bytes (14400 available)

  • #2


    I think it means, 'changed in the current session, but before the last save'.

    As for the memory error, what makes you say that?

    The report you have shown is code size, if you are running from RAM that will subtract form the available RAM. IF you are running from FLASH it will have no impact on the available RAM.
    Mark

    Comment


    • #3


      As for the memory error, what makes you say that?
      Code is runnning from RAM and if I add anything (new variable, function...) anywhere to code, code is running from Flash.

      Now I updated Workshop4 and copiler says:
      1rNEg3VRmdiiIT0u4f40zes0Xvp7ySvxp9IjlLPRLvLhc9HgjHsH0dDJfv4gyhU/cTad475LxXWZC0wr7320aSdXDJrr4OKZQmbv7mngn0pzsvkbxI2BTifjsde4Lsx+y+wTsK+vPqLBXwd6iIZm9858lf5K0fDp9erg kadBfHJPNMgvKlcOe23KniqSN6HtaWd959p4SSEaOomGbuPVlurZ79LjIjTaRcr7btHQzf4zJw9MqkbBPWvan3tyPvfGk6TbKRTD 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 3yTPL+P945auj3e+LzxPuX05xIrnwgE/kJa7/rB6jxH3q9YNwBAAD0J+lpoGdgBo75vEfv456Cxwx3aAu1XB7FOo9ljXlBT0cnt1PtYOufTP4YVxzzBQAAX84D0cBX+TbO95ZCgnZ sz5LrvbKax4UaZ+xrT61WvPCZntp5JRqkB0WE+k14Vpjl/FjyeQ/1JzLQ8/kjwqWNZ0+1R+O+ID1URmqdnk67QsYRkPU66eqxrL6dsvcAAAB8H49Ew/GvHufbjXLGwxhd3DzMOOJ6vPAmrsQL4perCBXFxcd+u6RBROq0bJE3hzpdezuEJ+MyPj11BtHQMFa60DxDG2CmqVdNPz5r7c8GZA IAAPA99BANtjhYP9hjr7EoZ4mbhxMSVA3gIQqM+cmzoUhV+IM6C91JFc0pl47YRGXUbZDo+wSM/rRcLEZ643ExYgWJGWB4YiAaAADg19Hj9YR9c92eotd3+cT73kk0GPHCPyoalGd5KxzkUf7uL8ntqyCejz6iIbb5w/S4iHSIBgAA+HU8EQ3nP2ac76nWWss4i21+2ZuHXr4ZL1xaGXs9kYtfrkItJ+Hs5RfpPgYlPWLkwlppxafnmzHPhsXSr+u10g+bRD mWnfJTxqq4ftEWUQAA+LE8+cmlHri7SZdegSPv4Zvfnfl2nG+jfCNeuPCa19C2hmz8cqeEva71y2fk+HnR2ljGmVbkVWLGs7fj09 OvGBs8zXS5p7XJHktXB4za6cd3h2gAAIBvAYc7AQAAACAERAMAAAAAQkA0AAAAACAERAMAAAAAQkA0AAAAACAERAMAAAAAQkA0AA AAACAERAMAAAAAQvwHReVfQuYnXccAAAAASUVORK5CYII=" class="bbc_img" />

      Comment


      • #4


        Run Time RAM usage is roughly

        38 bytes to mount the uSD
        570 bytes per file open.
        578 bytes per image control, plus 28 bytes per line in the .DAT file
        Plus any mem_Alloced memory

        Also, the message seems to indicate the code is running from RAM, have you missed the

        #MODE RUNFLASH

        statement?
        Mark

        Comment


        • #5


          With #MODE RUNFLASH statement program is working well so it seems the code size is too big to executing from RAM.
          So the value "Initial RAM size = 11515" is only informative but in fact can bee much bigger?

          Comment


          • #6


            Yes, the compiler only knows about 'staticly' used memory, it cannot estimate/analyse your program flow to work out how your program 'dynamically' uses memory

            You can use print(mem_Heap()) ; to see how much RAM is free at any point during execution
            Mark

            Comment


            • #7


              Ok, this is what I was looking for.
              Thank you!

              Comment

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